Optional Chaining
Access members of an optional value without unwrapping.
Optional chaining is a process for querying and calling properties, methods, and subscripts on an optional that might currently be nil
. If the optional contains a value, the property, method, or subscript call succeeds; if the optional is nil
, the property, method, or subscript call returns nil
. Multiple queries can be chained together, and the entire chain fails gracefully if any link in the chain is nil
.
Optional Chaining as an Alternative to Forced Unwrapping
You specify optional chaining by placing a question mark (?
) after the optional value on which you wish to call a property, method or subscript if the optional is non-nil
. This is very similar to placing an exclamation point (!
) after an optional value to force the unwrapping of its value. The main difference is that optional chaining fails gracefully when the optional is nil
, whereas forced unwrapping triggers a runtime error when the optional is nil
.
To reflect the fact that optional chaining can be called on a nil
value, the result of an optional chaining call is always an optional value, even if the property, method, or subscript you are querying returns a non-optional value. You can use this optional return value to check whether the optional chaining call was successful (the returned optional contains a value), or didn't succeed due to a nil
value in the chain (the returned optional value is nil
).
Specifically, the result of an optional chaining call is of the same type as the expected return value, but wrapped in an optional. A property that normally returns an Int
will return an Int?
when accessed through optional chaining.
The next several code snippets demonstrate how optional chaining differs from forced unwrapping and enables you to check for success.
First, two classes called Person
and Residence
are defined:
class Person {
var residence: Residence?
}
class Residence {
var numberOfRooms = 1
}
Residence
instances have a single Int
property called numberOfRooms
, with a default value of 1
. Person
instances have an optional residence property of type Residence?
.
If you create a new Person
instance, its residence
property is default initialized to nil
, by virtue of being optional. In the code below, john
has a residence
property value of nil
:
let john = Person()
If you try to access the numberOfRooms
property of this person's residence
, by placing an exclamation point after residence
to force the unwrapping of its value, you trigger a runtime error, because there's no residence
value to unwrap:
let roomCount = john.residence!.numberOfRooms
// this triggers a runtime error
The code above succeeds when john.residence
has a non-nil
value and will set roomCount
to an Int
value containing the appropriate number of rooms. However, this code always triggers a runtime error when residence
is nil
, as illustrated above.
Optional chaining provides an alternative way to access the value of numberOfRooms
. To use optional chaining, use a question mark in place of the exclamation point:
if let roomCount = john.residence?.numberOfRooms {
print("John's residence has \(roomCount) room(s).")
} else {
print("Unable to retrieve the number of rooms.")
}
// Prints "Unable to retrieve the number of rooms."
This tells Swift to “chain” on the optional residence
property and to retrieve the value of numberOfRooms
if residence
exists.
Because the attempt to access numberOfRooms
has the potential to fail, the optional chaining attempt returns a value of type Int?
, or “optional Int
”. When residence
is nil
, as in the example above, this optional Int
will also be nil
, to reflect the fact that it was not possible to access numberOfRooms
. The optional Int
is accessed through optional binding to unwrap the integer and assign the non-optional value to the roomCount
constant.
Note that this is true even though numberOfRooms
is a non-optional Int
. The fact that it's queried through an optional chain means that the call to numberOfRooms
will always return an Int?
instead of an Int
.
You can assign a Residence
instance to john.residence
, so that it no longer has a nil
value:
john.residence = Residence()
john.residence
now contains an actual Residence
instance, rather than nil
. If you try to access numberOfRooms
with the same optional chaining as before, it will now return an Int?
that contains the default numberOfRooms
value of 1
:
if let roomCount = john.residence?.numberOfRooms {
print("John's residence has \(roomCount) room(s).")
} else {
print("Unable to retrieve the number of rooms.")
}
// Prints "John's residence has 1 room(s)."
Defining Model Classes for Optional Chaining
You can use optional chaining with calls to properties, methods, and subscripts that are more than one level deep. This enables you to drill down into subproperties within complex models of interrelated types, and to check whether it's possible to access properties, methods, and subscripts on those subproperties.
The code snippets below define four model classes for use in several subsequent examples, including examples of multilevel optional chaining. These classes expand upon the Person
and Residence
model from above by adding a Room
and Address
class, with associated properties, methods, and subscripts.
The Person
class is defined in the same way as before:
class Person {
var residence: Residence?
}
The Residence
class is more complex than before. This time, the Residence
class defines a variable property called rooms
, which is initialized with an empty array of type [Room]
:
class Residence {
var rooms: [Room] = []
var numberOfRooms: Int {
return rooms.count
}
subscript(i: Int) -> Room {
get {
return rooms[i]
}
set {
rooms[i] = newValue
}
}
func printNumberOfRooms() {
print("The number of rooms is \(numberOfRooms)")
}
var address: Address?
}
Because this version of Residence
stores an array of Room
instances, its numberOfRooms
property is implemented as a computed property, not a stored property. The computed numberOfRooms
property simply returns the value of the count
property from the rooms
array.
As a shortcut to accessing its rooms
array, this version of Residence
provides a read-write subscript that provides access to the room at the requested index in the rooms
array.
This version of Residence
also provides a method called printNumberOfRooms
, which simply prints the number of rooms in the residence.
Finally, Residence
defines an optional property called address
, with a type of Address?
. The Address
class type for this property is defined below.
The Room
class used for the rooms
array is a simple class with one property called name
, and an initializer to set that property to a suitable room name:
class Room {
let name: String
init(name: String) { self.name = name }
}
The final class in this model is called Address
. This class has three optional properties of type String?
. The first two properties, buildingName
and buildingNumber
, are alternative ways to identify a particular building as part of an address. The third property, street
, is used to name the street for that address:
class Address {
var buildingName: String?
var buildingNumber: String?
var street: String?
func buildingIdentifier() -> String? {
if let buildingNumber = buildingNumber, let street = street {
return "\(buildingNumber) \(street)"
} else if buildingName != nil {
return buildingName
} else {
return nil
}
}
}
The Address
class also provides a method called buildingIdentifier()
, which has a return type of String?
. This method checks the properties of the address and returns buildingName
if it has a value, or buildingNumber
concatenated with street if both have values, or nil
otherwise.
Accessing Properties Through Optional Chaining
As demonstrated in Optional Chaining as an Alternative to Forced Unwrapping, you can use optional chaining to access a property on an optional value, and to check if that property access is successful.
Use the classes defined above to create a new Person
instance, and try to access its numberOfRooms
property as before:
let john = Person()
if let roomCount = john.residence?.numberOfRooms {
print("John's residence has \(roomCount) room(s).")
} else {
print("Unable to retrieve the number of rooms.")
}
// Prints "Unable to retrieve the number of rooms."
Because john.residence
is nil
, this optional chaining call fails in the same way as before.
You can also attempt to set a property's value through optional chaining:
let someAddress = Address()
someAddress.buildingNumber = "29"
someAddress.street = "Acacia Road"
john.residence?.address = someAddress
In this example, the attempt to set the address
property of john.residence
will fail, because john.residence
is currently nil
.
The assignment is part of the optional chaining, which means none of the code on the right-hand side of the =
operator is evaluated. In the previous example, it's not easy to see that someAddress
is never evaluated, because accessing a constant doesn't have any side effects. The listing below does the same assignment, but it uses a function to create the address. The function prints “Function was called” before returning a value, which lets you see whether the right-hand side of the =
operator was evaluated.
func createAddress() -> Address {
print("Function was called.")
let someAddress = Address()
someAddress.buildingNumber = "29"
someAddress.street = "Acacia Road"
return someAddress
}
john.residence?.address = createAddress()
You can tell that the createAddress()
function isn't called, because nothing is printed.
Calling Methods Through Optional Chaining
You can use optional chaining to call a method on an optional value, and to check whether that method call is successful. You can do this even if that method doesn't define a return value.
The printNumberOfRooms()
method on the Residence
class prints the current value of numberOfRooms
. Here's how the method looks:
func printNumberOfRooms() {
print("The number of rooms is \(numberOfRooms)")
}
This method doesn't specify a return type. However, functions and methods with no return type have an implicit return type of Void
, as described in Functions Without Return Values. This means that they return a value of ()
, or an empty tuple.
If you call this method on an optional value with optional chaining, the method's return type will be Void?
, not Void
, because return values are always of an optional type when called through optional chaining. This enables you to use an if
statement to check whether it was possible to call the printNumberOfRooms()
method, even though the method doesn't itself define a return value. Compare the return value from the printNumberOfRooms
call against nil
to see if the method call was successful:
if john.residence?.printNumberOfRooms() != nil {
print("It was possible to print the number of rooms.")
} else {
print("It was not possible to print the number of rooms.")
}
// Prints "It was not possible to print the number of rooms."
The same is true if you attempt to set a property through optional chaining. The example above in Accessing Properties Through Optional Chaining attempts to set an address
value for john.residence
, even though the residence
property is nil
. Any attempt to set a property through optional chaining returns a value of type Void?
, which enables you to compare against nil
to see if the property was set successfully:
if (john.residence?.address = someAddress) != nil {
print("It was possible to set the address.")
} else {
print("It was not possible to set the address.")
}
// Prints "It was not possible to set the address."
Accessing Subscripts Through Optional Chaining
You can use optional chaining to try to retrieve and set a value from a subscript on an optional value, and to check whether that subscript call is successful.
The example below tries to retrieve the name of the first room in the rooms
array of the john.residence
property using the subscript defined on the Residence
class. Because john.residence
is currently nil
, the subscript call fails:
if let firstRoomName = john.residence?[0].name {
print("The first room name is \(firstRoomName).")
} else {
print("Unable to retrieve the first room name.")
}
// Prints "Unable to retrieve the first room name."
The optional chaining question mark in this subscript call is placed immediately after john.residence
, before the subscript brackets, because john.residence
is the optional value on which optional chaining is being attempted.
Similarly, you can try to set a new value through a subscript with optional chaining:
john.residence?[0] = Room(name: "Bathroom")
This subscript setting attempt also fails, because residence
is currently nil
.
If you create and assign an actual Residence
instance to john.residence
, with one or more Room
instances in its rooms
array, you can use the Residence
subscript to access the actual items in the rooms
array through optional chaining:
let johnsHouse = Residence()
johnsHouse.rooms.append(Room(name: "Living Room"))
johnsHouse.rooms.append(Room(name: "Kitchen"))
john.residence = johnsHouse
if let firstRoomName = john.residence?[0].name {
print("The first room name is \(firstRoomName).")
} else {
print("Unable to retrieve the first room name.")
}
// Prints "The first room name is Living Room."
Accessing Subscripts of Optional Type
If a subscript returns a value of optional type—such as the key subscript of Swift's Dictionary
type—place a question mark after the subscript's closing bracket to chain on its optional return value:
var testScores = ["Dave": [86, 82, 84], "Bev": [79, 94, 81]]
testScores["Dave"]?[0] = 91
testScores["Bev"]?[0] += 1
testScores["Brian"]?[0] = 72
// the "Dave" array is now [91, 82, 84] and the "Bev" array is now [80, 94, 81]
The example above defines a dictionary called testScores
, which contains two key-value pairs that map a String
key to an array of Int
values. The example uses optional chaining to set the first item in the "Dave"
array to 91
; to increment the first item in the "Bev"
array by 1
; and to try to set the first item in an array for a key of "Brian"
. The first two calls succeed, because the testScores
dictionary contains keys for "Dave"
and "Bev"
. The third call fails, because the testScores
dictionary doesn't contain a key for "Brian"
.
Linking Multiple Levels of Chaining
You can link together multiple levels of optional chaining to drill down to properties, methods, and subscripts deeper within a model. However, multiple levels of optional chaining don't add more levels of optionality to the returned value.
To put it another way:
- If the type you are trying to retrieve isn't optional, it will become optional because of the optional chaining.
- If the type you are trying to retrieve is already optional, it will not become more optional because of the chaining.
Therefore:
- If you try to retrieve an
Int
value through optional chaining, anInt?
is always returned, no matter how many levels of chaining are used. - Similarly, if you try to retrieve an
Int?
value through optional chaining, anInt?
is always returned, no matter how many levels of chaining are used.
The example below tries to access the street
property of the address
property of the residence
property of john
. There are two levels of optional chaining in use here, to chain through the residence
and address
properties, both of which are of optional type:
if let johnsStreet = john.residence?.address?.street {
print("John's street name is \(johnsStreet).")
} else {
print("Unable to retrieve the address.")
}
// Prints "Unable to retrieve the address."
The value of john.residence
currently contains a valid Residence
instance. However, the value of john.residence.address
is currently nil
. Because of this, the call to john.residence?.address?.street
fails.
Note that in the example above, you are trying to retrieve the value of the street
property. The type of this property is String?
. The return value of john.residence?.address?.street
is therefore also String?
, even though two levels of optional chaining are applied in addition to the underlying optional type of the property.
If you set an actual Address
instance as the value for john.residence.address
, and set an actual value for the address's street
property, you can access the value of the street
property through multilevel optional chaining:
let johnsAddress = Address()
johnsAddress.buildingName = "The Larches"
johnsAddress.street = "Laurel Street"
john.residence?.address = johnsAddress
if let johnsStreet = john.residence?.address?.street {
print("John's street name is \(johnsStreet).")
} else {
print("Unable to retrieve the address.")
}
// Prints "John's street name is Laurel Street."
In this example, the attempt to set the address
property of john.residence
will succeed, because the value of john.residence
currently contains a valid Residence
instance.
Chaining on Methods with Optional Return Values
The previous example shows how to retrieve the value of a property of optional type through optional chaining. You can also use optional chaining to call a method that returns a value of optional type, and to chain on that method's return value if needed.
The example below calls the Address
class's buildingIdentifier()
method through optional chaining. This method returns a value of type String?
. As described above, the ultimate return type of this method call after optional chaining is also String?
:
if let buildingIdentifier = john.residence?.address?.buildingIdentifier() {
print("John's building identifier is \(buildingIdentifier).")
}
// Prints "John's building identifier is The Larches."
If you want to perform further optional chaining on this method's return value, place the optional chaining question mark after the method's parentheses:
if let beginsWithThe =
john.residence?.address?.buildingIdentifier()?.hasPrefix("The") {
if beginsWithThe {
print("John's building identifier begins with \"The\".")
} else {
print("John's building identifier doesn't begin with \"The\".")
}
}
// Prints "John's building identifier begins with "The"."